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help solve for x

2007-07-12 04:47:41 · 5 answers · asked by Rebecca D 1 in Science & Mathematics Mathematics

5 answers

In a common log, exponent = log(answer)

Then take 10 ^ exponent = answer

So, 10^2 = x^2
100 = x^2
x = +-10

2007-07-12 04:52:13 · answer #1 · answered by Andrew 4 · 0 0

Step by step solution:

First, the definition of log is that if x = b ^ Y, then
Y = log b (x) (pronounced "Y equals log to base b of x").

To solve this problem: 2 = log x^2, we see that x = 2 and Y = 2; but what is b?

The standard practice is that if no number appears, then use log base 10 - at least, this is what I was taught. Doing that, this problem is quite easy:

Ask yourself, "the base 10 log of what number squared gives 2?" Clearly, the base 10 log of 10 squared gives 2:

log 10 of (10 ^2) = 2.

So, x = 10.

Hope that helps.

2007-07-12 12:05:23 · answer #2 · answered by joelknight 1 · 0 0

When working with logs the power of x becomes the coefficient of the log. So:

2 = 2 log x
1= log x
if this is log base 10 then just raise 10 to power of the answer given (1) , so 10^1 is 10
answer is 10.

2007-07-12 11:57:49 · answer #3 · answered by 037 G 6 · 0 0

I assume you are using log base 10 so
10^2=10^log(x^2)
100=x^2
+-10=x

2007-07-12 11:52:02 · answer #4 · answered by leo 6 · 0 0

2 = LN(x^2)
e^2 = e^LN(x^2) = x^2

x = e

2007-07-12 11:52:37 · answer #5 · answered by fcas80 7 · 0 0

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