there are 4 blue and 12 white marbles in a bag. how many white marbles must be added to the bag to make the?

Question

there are 4 blue and 12 white marbles in a bag. how many white marbles must be added to the bag to make the probability of drawing a blue marble 1/6?

Answer 1

let total number of marbles in bag be x including 4 blue marbles
probability of drawing blue marble = 4/x
given 4/x = 1 / 6
so x = 24

additional white marbles needed = 24 - 4(blue) - 12(white)
= 8

Answer 2

When you have added the proper number of white marbles, the probability of drawing a blue marble will then be 1/6. This means that 1/6 of the marbles in the bag will be blue. Since we know that there will be 4 blue marbles, this means there will be a total of 4/(1/6)=24 marbles altogether. This means you added 24-16=8 white marbles.

Answer 3

You need to add 8 white marbles because then the ratio between them will be 4:24 or 1:6 (1 chance to get a blue marble per 6 chances to get a white marble)

Answer 4

P (blue) = 1 / 6 = 4 / 24
Require 4 blue and 24 total so there must be 20 white. This means that 8 white must be added to existing 12 white.

Answer 5

as it stands with 4 blue balls and 12 white balls, the probability of drawing out a blue ball is 4/(12+4) = 4/16 = 1/4

to get the probability to be 1/6 with just 4 blue balls, you would need a total of 4*6=24 balls in the bag. since you are at 16 originally you need to add 8 more white balls.

answer: 8 white balls

Answer 6

current total=16

total of blue=4

current probabilty=4/16=1/4

think what divided by 4 will make 6? because we have to get 4 to 1
therefore its 4/24=1/6

16 to 24 is an increase of 8

answer:8

Answer 7

You need to add 8 white ones to get your answer.
That would make your total about of marbles 24.

4/24=1/6

Answer 8

four