We're having an issue with this number here. Some say when you round 376 to 2 significant figures, it becomes 380. Is that for real? I think its 38, but because a lot of people say its 380, I'm getting quite confused. Pls. help!
2007-07-12 00:26:45 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It will be 3.8 *10^2
380 is not entirely correct because it signifies that the value is between 379.5 and 380.4 which would represent a precision that is beyond 2 significant digits.
2007-07-12 00:34:15 · answer #1 · answered by Ernst S 5 · 1⤊ 0⤋
Lots of people have the same problem rounding to sig figs. Can you identify the 2nd sig fig in 376 ? It`s the 7, which is 7 tens, so another way of asking the same question [in this case] would be, "round 376 to the nearest 10" The answer being 380. The difficulty that was apparent was the inability to identify the asked for figure of significance, and then relate it to the question.
Consider 0.0009283
The first figure of any significance, or value is the 9, the zeros
are called zero place holders. the 2nd s.f. is the 2, the 3rd 8,
and the 4th 3.
To write this number to [say] 3 s.f. is to go to the 8, and then
round the number in the usual way, giving 0.00093. Another
example, "round 23 592 to 3 s.f."
The 3rd s.f. is is the 5, which is 5 hundreds, so you`re being
asked to round the number to the nearest hundred, giving
23 600. I do hope this clarifies it for you, Twiggy.
2007-07-12 01:03:05 · answer #2 · answered by Twiggy 7 · 0⤊ 1⤋
380
2007-07-12 00:29:18 · answer #3 · answered by (♥_♥) 6 · 0⤊ 1⤋
Answer is 380 because 376 is closer to 380 than it is to 38.
Don`t be confused, this is easier than you think!
Good luck!
2007-07-15 07:28:14 · answer #4 · answered by Como 7 · 0⤊ 1⤋
3.8 * 10^2
10^2 is not included in significant figures so 3 and 8 are the only significant figures. so 3.8*10^2 is 2 significant figures
a rule in significant figures says that a 0 on the right side of a non zero digit is considered significant figures but if the 0 is at the left of the non zero digit is not considered as significant figure
2007-07-12 00:48:42 · answer #5 · answered by Lyrad 2 · 1⤊ 0⤋
there are 2 possible answers and it depends if you're using scientific notation or not.
if you're NOT using scientific notation... it's
380.
the zero is not considered a significant figure. if there is no decimal point, we count the significant figures starting from the first NONZERO digit going from RIGHT TO LEFT.
it's not 38 because, as the previous answerer said, zero serves as a place holder.
if you ARE using scientific notation, the answer is:
3.8 x 10^2.
this time, it's NOT 3.80 because 3.80 has 3 significant figures. if there IS a decimal point, we count the significant figures starting from the first NONZERO digit going from LEFT TO RIGHT.
hope that helps!!!
2007-07-12 01:04:49 · answer #6 · answered by sarah_hello_happyface 2 · 0⤊ 1⤋
I believe it's 380. It's like rounding to tens basically.
2007-07-12 00:48:34 · answer #7 · answered by Anonymous · 1⤊ 1⤋
380 the zero is not a significant digit but it is a place holder and can not be excluded.
2007-07-12 00:31:10 · answer #8 · answered by Brian K² 6 · 0⤊ 1⤋
That has to be 3.8*10^1.If u let it to be 380 it is said to be ambigous, its best for u to work them out in scientific notation
2007-07-12 00:47:47 · answer #9 · answered by Anonymous · 1⤊ 1⤋