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3 answers

Number of diagonals in a Polygon,

N = n(n-3)/2

Given,

n = 100

N = 100(100-3)/2

N = 4850

2007-07-11 22:32:36 · answer #1 · answered by ideaquest 7 · 0 0

n=100
C(n;2)-n= n(n-3)/2=100(100-3)/2=50*97= 4850 diagonals.

2007-07-11 22:30:46 · answer #2 · answered by iyiogrenci 6 · 0 0

diagonals=4850

2007-07-11 22:46:04 · answer #3 · answered by sanjeewa 4 · 0 0

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