Suppose a cone has a top diameter of 10 meters and is 10 meters high. Suppose you filled it to the brim with fresh water. What would be the pressure of the water at the bottom? Would it be any different to the pressure of water at the bottom of a 10 meter diameter cylinder?
2007-07-11 17:17:04 · 3 answers · asked by submergency 3 in Science & Mathematics ➔ Physics
Hydrostatic pressure depends on three things, and only three things:
1. The density of the fluid
2. The strength of the gravitational field
3. The depth of the point in question
The shape of the container does not matter at all.
2007-07-11 17:20:30 · answer #1 · answered by lithiumdeuteride 7 · 3⤊ 0⤋
Volume of a cone = (pi)(r^2)(h)/3 = approx. 2600,000cm³
Mass = 2600kg (since water is 1g/cm³)
F=ma -> (2600N)(10m/s²) = 26,000N
Area = Pi(r^2) = 80m²
kPa = N/m² -> 26000N/80m² = 325kPa
The cylinder would have more pressure at the bottom than the cone since there is more water filling the container (volume = Pi(r^2)(h))
The pressure would be 325kPa if it were a cylinder. (really rounded up though)
Hope this helps!
2007-07-11 19:05:14 · answer #2 · answered by Seb 1 · 0⤊ 1⤋
give it back or im calling the cops
2007-07-11 17:18:57 · answer #3 · answered by Anonymous · 0⤊ 2⤋