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7 answers

"Solve for x" means make the equation look like this:
X = . . . . . . .

Rearrange so that x is alone on the left side of this equation

5x - 2 = 3y
5x = 3y + 2
x = (3y + 2)/5

2007-07-11 16:49:01 · answer #1 · answered by bedbye 6 · 0 0

5x - 2=3y

You probably want something that looks like
x = something... right?

To do this you want to get x on one side and everything else on the other...

Add 2 to both sides.

5x - 2 + 2 = 3y + 2... Would agree that -2 +2 = 0? And that 5x+0=5x?

So now you have
5x= 3y+2

Now you want to get rid of the 5 somehow....
Well... if you multiply it by 1/5, you get 1... and 1x=x... right?

But if you multiply one side of the equation by 1/5, you have to multiply the other by 1/5 also... So you have
x = (1/5)(3y+2)

You could leave it like this, but there's another property called the distributive property of multiplication over addition: a(b+c)=ab+ac

so (1/5)(3y +2)= (3y+2)/5=3y/5+ 2/5

2007-07-12 00:03:56 · answer #2 · answered by gugliamo00 7 · 0 0

hmmm... first transpose -2 to the right side of the equation
5x -2 (+2) = 3y (+2)
5x = 3y + 2

then divide both sides of the equation by 5 to get x...

(5x) / 5 = (3y + 2) / 5
x = (3y + 2) / 5

2007-07-11 23:51:05 · answer #3 · answered by YANYAN 2 · 1 0

5x - 2=3y
5x=3y+2

x=3y/5+2/5

2007-07-11 23:45:58 · answer #4 · answered by iyiogrenci 6 · 0 0

add 2 to both sides
5x=3y+2

divide both sides by 5
x=(3y+2)/5

2007-07-12 00:08:33 · answer #5 · answered by Edesigner 6 · 0 0

Add 2 to both sides and then divide everything by 5.

x=3/5y+2/5

2007-07-11 23:48:32 · answer #6 · answered by John B 2 · 0 0

5x - 2 = 3y
5x=3y+2
x=(3y+2)/5

3y=5x-2
y=(5x-2)/3

2007-07-11 23:52:36 · answer #7 · answered by Gary 2 · 0 0

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