"Solve for x" means make the equation look like this:
X = . . . . . . .
Rearrange so that x is alone on the left side of this equation
5x - 2 = 3y
5x = 3y + 2
x = (3y + 2)/5
2007-07-11 16:49:01
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answer #1
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answered by bedbye 6
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5x - 2=3y
You probably want something that looks like
x = something... right?
To do this you want to get x on one side and everything else on the other...
Add 2 to both sides.
5x - 2 + 2 = 3y + 2... Would agree that -2 +2 = 0? And that 5x+0=5x?
So now you have
5x= 3y+2
Now you want to get rid of the 5 somehow....
Well... if you multiply it by 1/5, you get 1... and 1x=x... right?
But if you multiply one side of the equation by 1/5, you have to multiply the other by 1/5 also... So you have
x = (1/5)(3y+2)
You could leave it like this, but there's another property called the distributive property of multiplication over addition: a(b+c)=ab+ac
so (1/5)(3y +2)= (3y+2)/5=3y/5+ 2/5
2007-07-12 00:03:56
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answer #2
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answered by gugliamo00 7
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hmmm... first transpose -2 to the right side of the equation
5x -2 (+2) = 3y (+2)
5x = 3y + 2
then divide both sides of the equation by 5 to get x...
(5x) / 5 = (3y + 2) / 5
x = (3y + 2) / 5
2007-07-11 23:51:05
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answer #3
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answered by YANYAN 2
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5x - 2=3y
5x=3y+2
x=3y/5+2/5
2007-07-11 23:45:58
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answer #4
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answered by iyiogrenci 6
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add 2 to both sides
5x=3y+2
divide both sides by 5
x=(3y+2)/5
2007-07-12 00:08:33
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answer #5
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answered by Edesigner 6
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Add 2 to both sides and then divide everything by 5.
x=3/5y+2/5
2007-07-11 23:48:32
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answer #6
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answered by John B 2
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5x - 2 = 3y
5x=3y+2
x=(3y+2)/5
3y=5x-2
y=(5x-2)/3
2007-07-11 23:52:36
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answer #7
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answered by Gary 2
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