Find the antiderivative of u^4 + 3u^1/2/u^2......show your steps if you can. Much appreciated!?

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Find the antiderivative of u^4 + 3u^1/2/u^2......show your steps if you can. Much appreciated!?

2007-07-11 12:43:08 · 2 answers · asked by Gills 1 in Science & Mathematics ➔ Mathematics

2 answers

u^4 + 3u^1/2/u^2 = u^4 + 3u^(1/2-2)=u^4 + 3u^(-3/2)
Integral=(1/(4+1))u^(4+1) + (3/(-3/2 + 1))u^(-3/2 +1) + constant = (1/5)u^5 - (3*2)u^(-1/2) + constant=(1/5)u^(5) -6u^(-1/2) +constant

2007-07-11 13:03:53 · answer #1 · answered by aspx 4 · 0⤊ 0⤋

u^4 + 3u^1/2/u^2
= u^4 + 3u^-3/2
sO itegral is u^5/5 -6u^-1/2 + C

2007-07-11 19:54:52 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋