4.17 grams
5.21 grams
10.4 grams
20.8 grams
2007-07-11 11:51:45 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
10.4 grams
.2 mols BaCl2/ 1L * .25L = .05 mols BaCL2
.05 mols BaCl2 * 207 grams BaCL2 / 1 mol = 10.4
2007-07-11 11:58:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
10.4 g
MW=208
0.2 mol = 0.2 x 208 = 41.6
250 mL = 0.25 L sp 0.25 x 41.6 = 10.4 gm BaCl2
2007-07-11 11:58:47 · answer #2 · answered by skipper 7 · 0⤊ 0⤋
There are 208.36gBaCl2 in one mole, and moles/Liter=molarity
therefore:
(xgrams/208.36g/mol)/0.250Liters=0.200M
x=10.4 grams
2007-07-11 15:29:42 · answer #3 · answered by scott k 4 · 0⤊ 0⤋
10.4 grams
2007-07-11 12:02:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋
BaCl2 is 208.24 g/mole you'll need:
208.24g/mol x 0.200mol/l x 0.250l = 10.4g
2007-07-11 11:58:40 · answer #5 · answered by Flying Dragon 7 · 0⤊ 0⤋