If I am in a spaceship traveling at a constant 22,000 miles per hour through space in a straight line then how long would a normal Earth 24 hour period be for me on the space ship? I came up with 23 hours 59 minutes and 57.167 seconds. Is their any way to prove this? Thanks for your help.
2007-07-11 11:14:58 · 5 answers · asked by justask23 5 in Science & Mathematics ➔ Physics
i get that 22,000 miles per hour is about 3.3e-5*c
so that the lorentz factor 1/sqrt(1-(v/c)^2) is about 1 + 5.4e-10
so your clock would measure the earth's day to be about 24*3600*5.4e-10 = 4.7e-5 seconds longer than the clock on earth would measure. that is, assuming your clock is that accurate!
2007-07-11 11:42:35 · answer #1 · answered by vorenhutz 7 · 0⤊ 0⤋
I quote from the reference below:
The time will always be shortest as measured in its rest frame. The time measured in the frame in which the clock is at rest is called the "proper time".
The clock on your spaceship is at rest in its frame. This means that your spaceship's time is the shortest measured. So the time as measured on Earth is longest. I agree with the answer from vorenhutz.
2007-07-11 22:58:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Buy Isaac Asimov's book, Asimov's New Guide to Science, the formula is there. My keyboard lacks the symbols or I would pass it on to you. You will forever be happy you bought the book.
2007-07-11 18:21:03 · answer #3 · answered by johnandeileen2000 7 · 0⤊ 0⤋
The time dilation factor gamma is given by:
gamma = 1 / sqrt (1-(v/c)^2)
proper time = earth time / gamma
= earthtime * sqrt (1-(v/c)^2)
They give you earthtime and your velocity. Look up c. Plugnchug.
2007-07-11 18:31:21 · answer #4 · answered by Anonymous · 0⤊ 1⤋
according to my calculations, i get 23hrs, 59mins, and 59.99995356 secs.
2007-07-11 19:55:02 · answer #5 · answered by ftm821 2 · 0⤊ 0⤋