math hw help?

Question

If y^n = x^3n, where n, x, and y are positive integers, then what is x in terms of y?

a) ^3(root)y --> not 3(root)y. ex. ^3(root)27 = 3
b) (root) y
c) y/3
d) 3y
e) y^3

pls explain or show work

Answer 1

raise both sides of the equation to the power 1/(3n)

then you have y raised to n raised to 1/(3n)

= y raised to 1/3

so (a)

Answer 2

why do you have math HW in the middle of summer? Bad boy taking summer school?

ANS: A.
x is the cube root of y

Answer 3

(a).

y^n = x^3n

Taking the 3*n'th root of both sides, you get:

y^(n/3n) = x^(3n/3n)
y^(1/3) = x

So x is the cube-root of y.

Answer 4

actually carolina, im not a "bad boy". im jus taking SAT prep for next school year and its a program where they give hw... its not summer school. i dont take summer school with 3.9 GPA

thanks everybody for helping :-)