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Calculate the voltage across the 7.300 Ohm resistor. Please show your work.

http://www.geocities.com/trunks11111/theresistors.jpg

2007-07-11 09:44:37 · 4 answers · asked by Nate-dawg 2 in Science & Mathematics Physics

4 answers

yes I do.

If I showed my work, it would show that I drew the circuit as often as I needed to treat each battery separately, then showing the voltage drop from that one battery across the 7.3 volts (being careful to note the direction of the drop).

Then I would simply sum all the voltages for that one resistor (being careful with signs).

2007-07-11 09:51:39 · answer #1 · answered by Raymond 7 · 2 0

You are measuring voltage drop, if the circuit contains only one load the voltage drop will be equal the voltage supplied.

2007-07-14 06:07:24 · answer #2 · answered by johnandeileen2000 7 · 0 0

I won't do your homework for you, but I'll get you started.

Draw two current loops. I1 on the top loop. I2 on the bottom loop. I'll make them both clockwise.

The voltage drop around both loops must be zero. I'll do the top loop.

14V - (4+1 ohms)I1 - (4.5 + 1.5 ohms)(I1 - I2) - 24V - (3 ohms)I1 = 0

You can do the other loop.

Two equations. Two unknowns. Do the algebra. Solve for the currents I1 and I2.

Only I2 goes through the 7.3 ohm resistor, so the voltage drop will be 7.4 ohm * I2.

Have fun with that.

2007-07-11 09:52:06 · answer #3 · answered by Anonymous · 0 3

Zero.
You didn't connect it to a voltage source.

2007-07-11 09:53:07 · answer #4 · answered by Anonymous · 0 2

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