simplify the following expression: log a (1/square root 'a')?

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2007-07-11 09:29:23 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

loga(a^(-1/2)) = -(1/2)loga(a)= -1/2

2007-07-11 09:34:40 · answer #1 · answered by supastremph 6 · 0⤊ 0⤋

(1/square root of a) = 1/a^(1/2) or a^(-1/2)

The expression simplifies to log[a^(-1/2)]

If its base a, the expression simplifies to -1/2.

2007-07-11 09:34:14 · answer #2 · answered by jjsocrates 4 · 0⤊ 0⤋

log(base a) 1/sqrt(a)

= log(base a) 1/a^1/2

= log(base a) a^-1/2

= -1/2log(base a) a

= -1/2 (1)

= -1/2

2007-07-11 09:38:09 · answer #3 · answered by frank 7 · 0⤊ 0⤋

I am assuming you mean log(base a) ( 1/sqrt(a) ).
1/sqrt(a) = a^(-1/2).
The logarithm is therefore -1/2.

2007-07-11 09:34:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋