Find the size of a hypothenuse if one side of a right triangle is 3r and the other side is 2r.
2007-07-11 08:11:18 · 8 answers · asked by Angel_Wolf 2 in Science & Mathematics ➔ Mathematics
If h is the length of the hypotenuse, then:
h^2 = (3r)^2 + (2r)^2
= 9r^2 + 4r^2
= 13r^2
h = r sqrt(13).
2007-07-11 08:25:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋
let hypotenuse = h
h ² = (2r)² + (3r)²
h ² = 4 r² + 9 r²
h ² = 13 r²
h = â13 r
2007-07-15 13:30:28 · answer #2 · answered by Como 7 · 0⤊ 0⤋
hipotenuse=sqrt(9r^2+4r^2)=rxsqrt(13). ASN
2007-07-11 15:22:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
r*sqrt(13), assuming it's a right triangle.
also, the angle between the hypotanuse and the longer side is 33.7 degrees.
2007-07-11 15:25:56 · answer #4 · answered by dbaum295 2 · 0⤊ 0⤋
(2r^)2 +( 3r^2) = (cr^2)
4r^2+9r^= 13r^2
sq root 13r^2
2007-07-11 15:24:31 · answer #5 · answered by My point exactly 5 · 0⤊ 0⤋
(3r)^2+(2r)^2=c^2
9r^2+4r^2=c^2
c=(sqrt(13))r
2007-07-11 15:17:05 · answer #6 · answered by Red_Wings_For_Cup 3 · 0⤊ 0⤋
Is there a real answer for this? Or are you supposed to go into decimals?
2007-07-11 15:16:42 · answer #7 · answered by Anonymous · 0⤊ 1⤋
I am bad in math; sorry!
2007-07-11 15:20:35 · answer #8 · answered by Green eyes 4 · 0⤊ 2⤋