please help with multiplying this fraction..?

Question

.x - 3 . . . . . . . . . 1
(------)^3 times(-----)^2
. . 2 . . . . . . . . . .x-3

help and explanation would be appreciated.
please ignore the dots..

Answer 1

(X-3/2)^3 * (1/x-3)^2

(x^3 -27)/2 * 1 /x^2-9

x3-27/2x2-18

x3-3/2x2-2
?????

Answer 2

Rewrite the equation out at length. (x-3/2)(x-3/2)(x-3/2)(1/x-3)(1/x-3). Then cancell out two 'x-3's from the numerator and denominator, then your left with (x-3)(1)(1) in the numerator and (2)(2)(2) in the demominator. Multiply straight across to get x-3 divided by 8 or another way of writing it would be x-3/8 or x/8-3/8.

Answer 3

i read this as x-3 /2 times 1/x-3 correct?
if so multiply the two top numbers x-3 and 1 to get 1x-3. then do the bottom number s and x-3 to get 2x-3 place the answers back inorder so you get 1x-3 / 2x-3 then reduce the fraction by like terms so that you get 1/2

Answer 4

would that be [(((x-3)/2)^3)*((1/(x-3))^2]?

Answer 5

= [(x-3)^3/2^3][1^2/((x-3)^2]
Notice that (x-3)^3/(x-3)^2 = x-3
So your answer is (x-3)/8