Solve by using the quadratic formula. x^2=-5x-5?

Answer 1

x^2=-5x-5

Subtract terms on the right from both sides

x² + 5x + 5 = 0

We will solve using quadratic formula.

ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a

x = (-5 ± √(25 - 20))/2

x = (-5 ± √(5))/2

or

x ≈ -3.618, x ≈ -1.382
.

Answer 2

First, you have to get everything into the standard form of the quadratic equation:
AX^2 + BX + C = 0 where A, B, and C are constants.
After rearranging your equation, we have:
X^2 + 5X + 5 = 0. Here, A = 1, B = 5, and C = 5
The Quadratic Formula is:
X = [-B +/- (B^2 -4AC)^1/2]/2A
In words, that is a fraction where the numerator is:
minus B plus and minus the square root of (B squared minus 4AC) and the denominator is 2A. The plus and minus are to get the two roots.
If we substitute the numbers for the letters we get:
X = [-5 +/- (5^2 -4{1}{5}]/2{1} That reduces to:
X = [-5 +/- (25 - 20)^1/2]/2 That reduces to:
X = [-5 +/- (5)^1/2]/2 That reduces to:
X = -2.5 +/- (5)^1/2/2 In words, the two solutions are:
minus 2.5 plus one half the square root of 5 and
minus 2.5 minus one half the square root of 5

Answer 3

The quadratic formula is
(-b +/- √(b^2 - 4ac) ) / 2a
where a is the coefficient of the x^2, b the coefficient of x and c is the constant.
In your question, you need to move all the variables to one side then you have A=1, B=5 and C=5
The answer is then
( -5 +/- √5)/2 or -2 1/2 √5

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