2007-07-11 03:59:16 · 6 answers · asked by seahawk_1614 1 in Science & Mathematics ➔ Mathematics
x = ( -5 +/- sqrt(25 + 16) / 2
= ( -5 +/- sqrt(41) ) / 2.
2007-07-11 04:03:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋
By using the Quadratic formula you get ( -5 + sqrt(41) ) / 2 and ( -5 - sqrt(41) ) / 2
2007-07-11 11:07:22 · answer #2 · answered by Supergamer56 1 · 0⤊ 0⤋
x^2-5x-4=0
x=1/2[5+/-sqrt(25+16)]=1/2[5+/-sqrt(41)]. ANS.
2007-07-11 11:04:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a = 1
b = 5
c = -4
x = (-5 +/- sqrt(5^2 - 4 * 1 * -4))/(2 * 1)
x = (-5 +/- sqrt(25 + 16))/2
x = (-5 +/- sqrt(41)) / 2
x = -5/2 +/- sqrt(41)/2
If you have to eliminate the radical, sqrt(41) =~ 6.4
sqrt(41)/2 =~ 3.2
So x = -2.5 + 3.2 or -2.5 - 3.2
x = .7 or -5.7
2007-07-11 11:07:08 · answer #4 · answered by TychaBrahe 7 · 1⤊ 0⤋
x = -b +- sqrt(b^2 -4ac) / 2a
x = -5 +- sqrt ( 25 - 4(1)(-4) / 2(1)
x = -5 +-sqrt ( 41) / 2
2007-07-11 11:02:55 · answer #5 · answered by gfulton57 4 · 0⤊ 0⤋
[-5 +/- (41)^0.5]/2
X(+)= 0.701..
X(-)= -5,7..
2007-07-11 11:05:15 · answer #6 · answered by Ferrero 1 · 0⤊ 0⤋