If the garden box has dimensions x by x feet and an area in square feet equal to the perimeter in feet, what is the value for x that satisfies the requirements? (Hint: The box is a square.)
2007-07-11 03:52:03 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4 ft.
2007-07-11 03:54:14 · answer #1 · answered by mattside_bic 2 · 0⤊ 0⤋
Perimeter is x by y
Area is xy
Since box is a square, Perimeter = 2(x+x) =4x, and
Area=perimeter
Therefore xy =x(x) =x^2, and x^2=4x
From which x^2 - 4x = 0, x(x-4) =0
Either x=0 or x-4 =0 [In order to get the equation to
equal zero, at least one of the factors must be zero]
x=0 makes no practical sense, so x-4=0 yielding
x=4 is our answer
Hope this helps
2007-07-11 04:04:05 · answer #2 · answered by Grampedo 7 · 0⤊ 0⤋
Perimeter = 4x
Area (in square feet) = x^2
x^2 = 4x
x = 4
The length of each side is 4, and both the perimeter and area are 16.
2007-07-11 03:56:14 · answer #3 · answered by Kyrix 6 · 0⤊ 0⤋
perimter = area
4x = x^2
x = 4
4x4 = 16 (4+4+4+4)
4^2 = 16
2007-07-11 03:58:31 · answer #4 · answered by Donny Dutch 4 · 0⤊ 0⤋
perimeter = 4x
area = x^2 = x*x
x^2=4x divide by x
x=4
2007-07-11 03:57:37 · answer #5 · answered by Martin S 7 · 0⤊ 0⤋
the height
2016-04-01 09:00:04 · answer #6 · answered by ? 4 · 0⤊ 0⤋
x x x
perimeter=area
4x=x^2
x=0,4
answer=4ft, each side=x=4ft.
2007-07-11 03:58:10 · answer #7 · answered by Anonymous · 0⤊ 0⤋
x will = to Y
2007-07-11 03:59:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋
no clue sorry
2007-07-11 04:14:53 · answer #9 · answered by Anonymous · 0⤊ 0⤋