benzophenone oxime mechanism?

Answer 1

I am not sure what you are asking but if it is the conversion of benzophenone to benzophenone oxime here is the answer. React a solution of hydroxylamine hydrochloride and benzophenone and a little base such as triethylamine or Hunigs base (Diisopropylethylamine). Stir them up (it will probably require heating since it is a relatively hindered ketone). The product will then be benzophenone oxime. What happens is the base free bases the hydroxylamine hydrochloride to hydroxylamine. This reacts at the carbonyl carbon of the benzophenone to give the tetrahedral intermediate called (hydroxyamino)diphenylmethanol. This then dehydrates to form the desired product. I wish I could draw this out for you so you could see it. Hope you find it helpful

Answer 2

(C6H5)2C=NOH + H+ ===> (C6H5)2C=NOH2+

(C6H5)2C=NOH2+ ===> (C6H5)2C=N+ + H2O

(C6H5)2C=N+ ===> C6H5-C(+)=N(-)-C6H5 In addition to the C=N bond, C has a (+) charge and N a (-).

C6H5-C(+)=N(-)-C6H5 + H2O ===> C6H5-CO.NH-C6H5

In the last step, H2O adds to the -(+)C=N(-)- bond forming (+)H2O-C=N-, which loses H+ to give HO-C=N-, which in turn tautomerizes to give the benzanilide final; product.