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li (x) = ∫ dt / ln t [x = 0, x]
Is there a formula of li (x) which is more readily to be input into a calculator?

2007-07-11 01:59:31 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

You can calculate the logarithmic integral function from its series representation:

Li(x)
= γ + ln(|ln(x)|) + ln(x) + [ln(x)]² / (2 · 2!) + ... + [ln(x)]^n / (n · n!) + ....
= γ + ln(|ln(x)|) + Σ|n=1 → ∞| [ln(x)]^n / (n · n!)

or

Li(x) =
= γ + ln(|ln(x)|) + Σ|n=1 → ∞|{ (-1)^(n-1) · [ln(x)]^n / (n! · 2^(n-1)) · Σ|k=1 → (n-1)/2| 1/(2k+1) }

The later one converges more rapidly.

γ is the Euler Mascheroni constant
γ = 0.57721...


An alternative for large values of x is the asymptotic expansion:
Li(x) =
= x/ln(x) + Σ|n=0 → ∞|{ n! / [ln(x)]^n }·

2007-07-11 05:56:02 · answer #1 · answered by schmiso 7 · 0 0

Unfortunately, no.
li(x) is nonelementary and the only way
to get a grip on it is to use infinite series.
BTW, li(x) is important in the study of prime numbers.
It gives an estimate for the number of primes
less than or equal to x.

2007-07-11 10:04:56 · answer #2 · answered by steiner1745 7 · 0 0

do your own homework

2007-07-17 14:29:32 · answer #3 · answered by weazel 2 · 1 2

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