(x-9)(x-6)=0 implies x=9,6
(x-19)(x-7)=0 implies x=19,7
(x-1)(2x-3)=0 implies x=1,3/2
(x-1)(3x-2)=0 implies x=1,2/3
(x+1)(3x-16)=0 implies x= -1,16/3
2007-07-11 00:57:03
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answer #1
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answered by libraboy28 2
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Q1)
x² + 15x + 54 = 0
x² + 9x + 6x + 54 = 0
x(x + 9) + 6(x + 9) = 0
(x + 6)(x + 9) = 0
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Q2)
x² - 26x + 133 = 0
x² - 19x - 7x + 133 = 0
x(x - 19) + 7(x - 19) = 0
(x + 7)(x - 19) = 0
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Q3)
2x² - 5x + 3 = 0
2x² - 2x - 3x + 3 = 0
2x(x - 1) - 3(x - 1) = 0
(2x - 3)(x - 1) = 0
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Q4
3x² - 5x + 2 = 0
3x² - 3x - 2x + 2 = 0
3x(x - 1) - 2(x - 1) = 0
(3x - 2)(x - 1) = 0
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Q5)
3x² - 13x - 16 = 0
3x² + 3x - 16x - 16
3x(x + 1) - 16(x + 1) = 0
(3x - 16)(x + 1)
- - - - - - - - -s-
2007-07-11 08:38:53
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answer #2
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answered by SAMUEL D 7
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Q1) x^2 + 15x + 54 = 0
(x+6)(x+9)=0
x= -6 or -9
Q2) x^2 - 26x + 133 = 0
(x+19)(x+7)=0
x= -19 or -7
Q3) 2x^2 - 5x + 3 = 0
(2x-3)(x-1)=0
x=3/2, 1
Q4) 3x^2 - 5x + 2 = 0
(3x-2)(x-1)=0
x=3/2, 1
Q5) 3x^2 - 13x - 16 = 0
(3x-16)(x+1)=0
x=16/3, -1
2007-07-11 08:13:54
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answer #3
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answered by zohair 2
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Q1) x^2 + 15x + 54 = 0........(x+8)(x+7) = 0
Q2) x^2 - 26x + 133 = 0.......(x-7)(x-19) = 0
Q3) 2x^2 - 5x + 3 = 0...........(2x-3)(x-1) = 0
Q4) 3x^2 - 5x + 2 = 0...........(3x-2)(x-1) = 0
Q5) 3x^2 - 13x - 16 = 0 .......(3x-16)(x+1) = 0
2007-07-11 07:34:13
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answer #4
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answered by MamaMia © 7
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1) (x - 9)(x -6) ; x = 6, 9
2) (x - 7)(x - 19); x = 7, 19
3) (2x - 1 )( x - 3 ); x = 1/2, 3
4) (3x - 1)( x - 2); x = 1/3, 2
5) (3x - 16)(x + 1); x =16/3 , -1
2007-07-11 07:35:14
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answer #5
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answered by Rafael J 4
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1) (x - 9)(x -6) ; x = 6, 9
2) (x - 7)(x - 19); x = 7, 19
3) (2x - 1 )( x - 3 ); x = 1/2, 3
4) (3x - 1)( x - 2); x = 1/3, 2
5) (3x - 16)(x + 1); x =16/3 , -1
2007-07-11 07:37:39
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answer #6
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answered by TENBONG 3
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x= -9,-6, x=19,7 x=3/2,1 x=2/3,1 x=16/3,-1 easy as pie.Could plz put questions with bigger powers than 2 like 3 or 4.That would be a real challenge!
2007-07-11 08:09:49
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answer #7
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answered by tbaz4us 2
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do ur own math quiz, ur never gonna learn n-e thing if u copy
2007-07-11 08:48:28
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answer #8
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answered by Anonymous
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