A car traveling at 60km/hr overtakes another car traveling at 42km/hr. Assuming each car to be 5m long, find the time taken during the overtake and the total road distance used for the overtake.
2007-07-10 19:26:34 · 6 answers · asked by THE ALCHEMIST 3 in Education & Reference ➔ Homework Help
No they don't leave the same place a t the same time. If this were true then body with high speed would have already been in the front.
2007-07-10 19:37:59 · update #1
assuming both cars travel at constant speed...
and the "overtake time":
STARTS at the point where the FRONT OF FAST CAR is in-line with REAR OF SLOW CAR, and
ENDS when the REAR OF FAST CAR is IN LINE WITH FRONT OF SLOW CAR....
then....
During the overtake, FAST CAR travels 10 meters more than SLOW CAR....
Convert 60 km/hr and 42 km/hr to m/s
during the same time:
d,fast = (v,fast)*t = d,slow + 10 m
d,slow = (v,slow)*t
d,fast-d,slow = 10 meters = (v,fast-v,slow)t
solve for t (seconds)
the road distance is how far FAST CAR travels, d,fast.
2007-07-10 19:37:29 · answer #1 · answered by Dominic D 2 · 0⤊ 0⤋
Look at it this way:
The relative speed of the 2 cars is 60 - 42 = 18 km/hr
18km/hr = 18000m in 60 mins
= 300m per min
= 5m per second
Since, in the overtake, the faster car has to travel a total distance of 10m, the question resolves itself into " how long does it take to travel 10m at 5m/sec " so the overtake takes 2 seconds. Hope this helps, Twiggy.
2007-07-11 06:00:10 · answer #2 · answered by Twiggy 7 · 0⤊ 0⤋
Did they leave at the same place and the same time?
2007-07-11 02:34:52 · answer #3 · answered by Too Curious 3 · 0⤊ 0⤋
where did they start? did they start at the same place? or what?....if they started at the same place i would say the car that had the more torque off the line...so i would say a split second
2007-07-11 02:35:21 · answer #4 · answered by jdog44442003 3 · 0⤊ 0⤋
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2007-07-11 02:30:39 · answer #5 · answered by ella 1 · 0⤊ 0⤋
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2007-07-11 02:30:32 · answer #6 · answered by swanjarvi 7 · 0⤊ 0⤋