the 17 is suposed to look like a small 17(underscored)
2007-07-10 16:48:31 · 4 answers · asked by lilrascal 1 in Science & Mathematics ➔ Mathematics
log[(base 17) 125] = log[(base 17) 5³]
= 3*log[(base 17) 5]
2007-07-10 16:54:14 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
Log 17 125
Set it = to x
Log 17 125 =x
change to exponential
x^17 = 125
take the log of both sides. When u take the log, the power comes to the front.
17 log x = log 125
log x = log 125 / 17
log x = .12335
anti log both side
x = 1.3285
2007-07-10 23:58:50 · answer #2 · answered by Brilliant Queen (BQ)_forever !!! 5 · 0⤊ 0⤋
Why don't you ask Mr. Jones in class tomorrow? Caught ya. I won't say anything, but that is quite a coincidence isn't it?
Would that be question 11 that is really question 12, look closely and wonder, who is this on-line?
I guess two questions from the same test is astronomical, you should discuss the probability of this happening.
By the way, none of these people have the correct answer, one however is close.
Don't freak, I'm not him. You are very resourceful.
2007-07-11 00:21:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
17 is base of the log.
=log(base 17)125
=log(base 10)125/log(base 10)17
The log values of 125 & 17 can be seen from the log table. These values are for base 10.
=2.097/1.230
=1.7049
2007-07-10 23:59:22 · answer #4 · answered by Jain 4 · 0⤊ 0⤋