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The sum of three consecutive odd integers is 72. Write the equation you would use to find a solution.

a. x + (x + 1) + (x + 2) = 72

b. x + (x + 1) + (x + 3) = 72

c. x + (x + 2) + ( x + 4) = 72

d. 2x + 6 = 72

2007-07-10 16:10:18 · 10 answers · asked by Gloria T 1 in Science & Mathematics Mathematics

10 answers

(C)

Three consecutive odd integers would be a number, 2 more than it, and 2 more than the previous number. So, we have:

x + (x + 2) + (x + 2 + 2) = 72
x + (x + 2) + (x + 4) = 72

2007-07-10 16:14:00 · answer #1 · answered by yeeeehaw 5 · 1 0

I wouldn't use an equation. I would say "The sum of any three odd integers will be odd, so there are no solutions."

If it was consecutive even integers, I would probably use the equation
2x + 2(x+1) + 2(x+2) = 72
but the equation x + (x + 2) + (x + 4) = 72 would also be valid.
(Actually I'd probably just say "The average is 72/3 = 24, so the integers must be 22, 24 and 26.")

2007-07-10 16:19:21 · answer #2 · answered by Scarlet Manuka 7 · 1 0

This is a trick question. The sum of two odd integers is even. The sum of an odd and even integer is odd. The sum of three odd integers must be odd. 72 is not odd.

C) appears to be the best solution, but if you work it out, you'll find the value of x is 22, which is an even integer.

2007-07-10 16:21:10 · answer #3 · answered by stork5100 4 · 0 0

Three odd integers have an odd sum, so there aren't three consecutive odd integers that add up to 72. Two odds make an even. An even and an odd make an odd. The closest answers are 69 (21,23,25) and 75 (23,25,27).

2007-07-10 16:17:36 · answer #4 · answered by nstone 2 · 0 0

Some of the answers given are incorrect.

If you add up three odd integers, the result will ALWAYS be odd, so it cannot be 72.

So either you have asked the question incorrectly, or it is a trick question. (c) is correct, but it gives the answers 22, 24, 26, which are even, as explained.
.

2007-07-10 16:24:57 · answer #5 · answered by tsr21 6 · 0 0

c. x + (x + 2) + ( x + 4) = 72 is correct, but I would use
x-2+x+x+2=72 the 2's on the LHS cancel out.
3x=72
x-24 these are even integers, so there is no solution to the stated problem.

2007-07-10 16:15:41 · answer #6 · answered by yupchagee 7 · 0 0

the first odd integer. The second odd integer is the first +2. The third odd integer is the first +4. Using that, there's only 1 option there that fits... BUT this question may be flawed as this will give you 3 EVEN integers

2007-07-10 16:15:20 · answer #7 · answered by Shamus 2 · 1 0

C. is the correct answer.

If X is odd, then X+1 must be even, so A. and B. are incorrect.

2X + 6 can be broken down into x + (x+6) which are only two numbers, and they're not consecutive, either, so D. is incorrect.

2007-07-10 16:16:48 · answer #8 · answered by Rob 2 · 0 0

the answer is (C)

there are 3 consecutive ODD numbers, just like consecutive letters: abcde, except you can't use b or d because its supposed to be ODD, or every other letter: a_c_e

the difference from c to a is 2
the difference from e to a is 4

to get 'c' you have to do 'a+2'
to get 'e you have to do 'a+4'

or if a=x: x + (x+2) + (x+4) =72

i hope it's right

2007-07-10 16:44:39 · answer #9 · answered by imaan 1 · 0 0

note

x + (x + 2) + (x + 4) = 72
3x + 6 = 72
3x = 66
x = 22

so, there are no three consecutive odd integers whose sum is 72!

2007-07-10 16:17:54 · answer #10 · answered by Poetland 6 · 0 0

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