a pool shaped like a circle with diameter of 22yd .A ring-shaped path goes around the pool. Its width is 5yd?

Question

We are going to give a new layer of coating to the path. If one gallon of coating can cover 6yd^2 , how many gallons of coating do we need? Note that coating comes only by the gallon, so the number of gallons must be a whole number. (Use the value 3.14 for Pi .)

Answer 1

The pool's radius is 11 yd. So its area is 11*11*pi, which is about 380 square yd.

The path adds 5 yd to the radius, so the path and pool put together have an area of 16 * 16 * pi, which is about 804 square yd.

The path itself is the difference of those two numbers (804 - 380 = 424). 424 square yd, divided by 6, equals about 70.7, so you'd need 71 gallons rounded up.

Answer 2

the diameter of the pool is 22yd
therefore its area is
=3.14*11*11 yd^2
=379.94 yd^2
the dia of the pool includding the path is
22+10
=32 yd
The area of the pool with the pathis
3.14*16*16
=803.84 yd^2
Hence the area of the pathis
803.84-379.94
=423.9 yd^2
therefore coating required
=423.9/6
=70.65 or 71 gallons(converted to nearest next gallon)

Answer 3

Easy.

Outer Radius R = 11 +5 = 16 yds

Inner Radius ( r) = 11 yd.s

Area of the path = Pi ( R+r) ( R-r)

= 3.14 * (16 + 11) * (16 - 11)

= 3,14 * 27 * 5

= 423.90 sq. yds.

For 6 sq.yds, the coat needed = 1 gallon

For 423.90 sq. yds, the quantity of coat needed

= 423.90 divided by 6 = 70.65 gallons\

= 71 gallons ( rounding off to the digit) ANSWER

Give me my 10.

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