How do I begin this? The examples in my book are really confusing.
2007-07-10 13:15:39 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
change it to multiplication by flipping the second fraction
6/x^2*x^3/9
now we cancel out x^2 giving us x on the top
2x/3 (6/9=2/3)
2007-07-10 13:20:36 · answer #1 · answered by leo 6 · 0⤊ 0⤋
First put everything into a common numerator and denominator. (6/x^2)/(9/x^3) simplifies to (6*x^3)/(9*x^2). Then reduce the numbers. 6/9 = 2/3. So now its (2*x^3)/(3*x^2). Now you reduce the x values. divide x^2 from both sides leaving (2*x)/3 and thats the most simplified answer.
2007-07-10 13:25:59 · answer #2 · answered by whun133 1 · 0⤊ 0⤋
When you have a fraction divided by a fraction, invert and multiply.
6/x^2 divided by 9/x^3 =
6/x^2 times (x^3)/9 = (multiply top by top and bottom by bottom)
6x^3 / 9x^2 = (then reduce the fraction)
6x / 9 = 2x/3
2007-07-10 13:22:07 · answer #3 · answered by Steve A 7 · 0⤊ 0⤋