a figures segments CD and CE are tangent to the circle centered at 'O'.Given that OD=3.2 and OC=6.8,find CE

0 ⤊

2007-07-10 12:12:18 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

c is the point of tangency

2007-07-10 12:22:04 · update #1

CE^2 = (OC-3.2)(OC+3.2)
CE^2 = (6.8-3.2)(6.8+3.2) = 36
OC = sqrt(36) = 6

2007-07-10 12:26:36 · answer #1 · answered by ironduke8159 7 · 0⤊ 1⤋

Do you have a figure? If not, well, is C the point of tangency?

2007-07-10 19:20:38 · answer #2 · answered by Ian 2 · 0⤊ 1⤋

[CE]^2=[CD]^2=[OD]^2+[OC]^2

=6.8^2+3.2^2

=Root56.8, sorry no calculator........................

2007-07-10 19:51:05 · answer #3 · answered by Twiggy 7 · 0⤊ 0⤋