a pilot attempts to fly a plane to an aiport 180 km E 20 N of its initial position. a wind blowing at 90 km/h acts on the plane E 40 N if the plane lands 0.4 h after take off find its airspeed heading
any help please?
im stuck with this on
2007-07-10 10:48:19 · 3 answers · asked by sweetheart 2 in Science & Mathematics ➔ Physics
Ground speed = 180/0.4 = 450 kph
Vn = 450sin20° - 90sin40° = 96.05818 kph
Ve = 450cos20° - 90cos40° = 353.91768 kph
V = 366.72 kph @ E 15.185° N
*To those who do not use it, your direction convention, i.e. E 20 N is ambiguous. It could read 20° East of North or 20° North of East. Accepted international convention uses the 360° compass circle with N at 0° and E at 90°.
2007-07-10 12:13:39 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
This difficulty is incredibly puzzling me besides.what's the question? i will basically wager that the question is: at what perspective is the rope related to the field. is this the question? if so, answer as follows: using fact the field strikes at a relentless velocity, the ensuing or internet tension is 0. consequently the utilized tension in a horizontal path could desire to be equivalent to the friction tension: utilized tension horizontal path = 25N 25N is the horizontal ingredient of a 43N tension at an perspective ? with the floor. sparkling up for ?. cos ? = 25/40 3 cos ? = 0.5814 ? = fifty 4.40 5° above the horizontal The rope replaced into at an perspective of fifty 4.40 5° above the horizontal
2016-10-19 03:43:33 · answer #2 · answered by ? 4 · 0⤊ 0⤋
what does the question ask for?
2007-07-10 11:37:57 · answer #3 · answered by miss_arabian_gulf 4 · 0⤊ 0⤋