If you have a parabola on a graph and three of the points are...
(5, 18) (9, 102) (-2, 25) How can you find the quadratic function, or equation, based on the information given.
2007-07-10 10:17:11 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
y = Ax² + Bx + C
Plug in the points to solve A, B & C.
You will have a system of 3 linear equations in 3 variables.
I'll give the first:
18 = 25A + 5B + C
... continue then find the values of A, B & C. (Easier if you have a graphics calculator, one that can solve a matrix.)
d:
2007-07-10 10:25:45 · answer #1 · answered by Alam Ko Iyan 7 · 1⤊ 0⤋
y = ax^2+bx+c <-- Standard quadratic equation
18 = 25a +5b +c
102= 81a+9b+c
25 = 4a-2b + c
Solve the above 3 equations simultaneously for a,b,and c. Then plug the values foun in the standard quadratic equation.
2007-07-10 17:30:28 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
y=ax^2+bx+c
solve:
25a+5b+c=18 and
81a+9b+c=102 and
4a-2b+c=25
2007-07-10 17:29:33 · answer #3 · answered by cvet_che 2 · 0⤊ 0⤋