2007-07-10 09:55:13 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
factor out 2
2 (x^2 + 4x + 3)
look for two numbers that multiply to 3 and add to 4
the two numbers are 1 and 3
2 (x + 1) (x + 3)
2007-07-10 09:59:04 · answer #1 · answered by 7 · 0⤊ 0⤋
Since all the terms are positive, you're looking at something of the form:
(x + a)(2x + b)
where a*b = 6
and 2a + b = 8
You can calculate this out, but I just used trial and error to figure out that a=3 and b=2.
The factored equation is (x+3)(2x+2).
Factoring out a 2 from the second parentheses, that turns into 2*(x+3)(x+1).
Hope that helps!
2007-07-10 17:00:43 · answer #2 · answered by Bramblyspam 7 · 0⤊ 0⤋
2x^2+8x+6= 2(x^2+4x+3)=2(x+1)(x+3)
2007-07-10 16:59:32 · answer #3 · answered by uk_wildcat96 2 · 0⤊ 0⤋
(x + 1) * (x + 2) * 2
2007-07-14 06:28:19 · answer #4 · answered by Jun Agruda 7 · 2⤊ 0⤋
2x^2 +8x+6
x(2x+2) +6(x+1)
(2x+2)(x+3)
2(x+1)(x+3)
And there you go
2007-07-10 17:11:50 · answer #5 · answered by firebolt 2 · 0⤊ 0⤋
(2x + 2)(x + 3)
2(x + 1)(x + 3)
2007-07-10 16:59:10 · answer #6 · answered by Becky M 4 · 0⤊ 0⤋
2(x^2+4x+3)
2(x+3)(x+1)
2007-07-10 17:11:03 · answer #7 · answered by kate 2 · 0⤊ 0⤋
2x^2+8x+6
=2X^2+6X+2X+6
=2X(X+3)+2(X+3)
=(2X+2)(X+3)
=2(X+1)(X+3)
2007-07-11 05:09:07 · answer #8 · answered by Sumita T 3 · 0⤊ 0⤋