Factoring Trinomials
2007-07-10 09:43:36 · 12 answers · asked by celeste m 1 in Science & Mathematics ➔ Mathematics
Since the last term (+42) is positive, the signs in the parentheses have to both be the same.
Since the middle term (-13x) is negative, the signs in the parentheses both have to be negative.
So you have something like (x-a)(x-b)
where a*b = 42 and (-a -b) = -13.
The factored version of the equation turns out to be:
(x-6)(x-7)
Hope that helps!
2007-07-10 09:49:29 · answer #1 · answered by Bramblyspam 7 · 0⤊ 0⤋
(x-6)(x-7)
Think about it this way. What 2 numbers add up to -13 and multiply to get 42. -6 and -7. And since theres no coefficient on the x^2, it's just an x
2007-07-10 16:47:25 · answer #2 · answered by llllarry1 5 · 0⤊ 0⤋
x^2-13x+42
= x^2-6x-7x+42
= x(x-6)-7(x-6)
(x-6)(x-7) Answer
2007-07-10 17:06:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x^2-13x+42
=( x-6)(x-7)
2007-07-10 16:49:02 · answer #4 · answered by God_Of_War 2 · 0⤊ 0⤋
(x-6)(x-7)
Check this by applying the foil method which would give you:
x^2-6x-7x+42
x^2-13x+42
2007-07-10 16:47:08 · answer #5 · answered by Dave O 2 · 0⤊ 0⤋
x^2-13x+42
x^2-6x-7x+42
x(x-6)-7(x-6)
(x-6)(x-7) Ans
2007-07-10 16:58:18 · answer #6 · answered by In Flames I Lay Dying 3 · 0⤊ 0⤋
x^2-13x+42
x^2-6x-7x+42
x(x-6)-7(x-6)
(x-6)(x-7) Ans
2007-07-10 16:52:55 · answer #7 · answered by MAHAANIM07 4 · 0⤊ 0⤋
What factors that make 42 also added or subtracted make -13 is what u should ask yourself.
negative six and negative seven.
(x-7) (x-6) the problem has two roots both six and seven
2007-07-10 16:50:16 · answer #8 · answered by Anonymous · 0⤊ 0⤋
x 2 - 13x +42
=X^2-6X-7X+42
=X(X-6)-7(X-6)
=(X-7)(X-6)
2007-07-11 05:10:42 · answer #9 · answered by Sumita T 3 · 0⤊ 0⤋
x^2 - 13x + 42
x^2 -7x - 6x + 42
x(x - 7) -6(x - 7)
(x - 7) (x - 6)
there u go.
2007-07-10 16:45:55 · answer #10 · answered by Anonymous · 0⤊ 0⤋