12x^2+42x-24
&
8x^2+6x-35
2007-07-10 07:10:01 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1.) 12x^2 + 24x - 24
6(2x^2 + 7x - 4)
6(2x^2 + 8x - x - 4)
6(2x(x + 4) -1(x + 4))
6(2x - 1)(x+4)
2.) 8x^2 + 6x - 35
8x^2 + 20x - 14x - 35
4x(2x + 5) - 7(2x + 5)
(4x - 7)(2x + 5)
there u go.
2007-07-10 07:14:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Question 1
= 6 ( 2x² + 7x - 4 )
= 6 (2x - 1) (x + 4)
Question 2
= (4x - 7) (2x + 5)
2007-07-10 07:44:07 · answer #2 · answered by Como 7 · 0⤊ 0⤋
I just finished algebra and I couldn't find any possible factors sorry. You know that you need to be able to find all the factors of the last term and those two factors need to add together to equal the middle term. Check this site out.
http://library.thinkquest.org/20991/alg/factoring.html
2007-07-10 07:38:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
6(2x^2 + 7x - 4)
6(2x - 1)(x + 4)
(4x - 7)(2x + 5)
2007-07-10 07:15:23 · answer #4 · answered by therealchuckbales 5 · 0⤊ 0⤋
6(-4 + -1x)(1 + -2x)
(-5 + -2x)(7 + -4x)
use this site, it will walk you through each step
2007-07-10 07:18:54 · answer #5 · answered by bookgrl 4 · 0⤊ 0⤋
12x^2+42x-24
=6(2x^2+7x-4)
=6(2x^2+8x-x-4)
=6{2x(x+4)-1(x+4)}
=6(x+4)(2x-1)
8x^2+6x-35
=8x^+20x-14x-35
=4x(2x+5)-7(2x+5)
=(2x+5)(4x-7)
2007-07-10 07:14:59 · answer #6 · answered by alpha 7 · 0⤊ 0⤋