cube root of 24+ 5 cuberoot of 81 would it be 17 times the cube root of 3?

Answer 1

cube root of 24 + 5 cuberoot of 81

cuberoot (8*3) + 5 cuberoot(27*3)

2 cuberoot (3) + 3*[5 cuberoot(3)]

2 cuberoot(3) + 15 cuberoot(3)

17 cuberoot (3)

Yep, it would be 17 times the cuberoot of 3 ;)
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Answer 2

Yes. Cube root of 24 is 2 cube root of 3. Cube root of 81 is 3 cube root of 3. Five times that, plus the first thing, is 17 times cube root of 3.

Answer 3

Yes, it would be 17 times cube root of 3

The cube root of 24 is 2 times cube root of 3, because 8 * 3 is 24 and 8 is 2 cubed and you take out the 2 and place it in front of the cube root of 3.

The cube root of 81 is 3 times cube root of 3, because 27 * 3 is 81 and 27 is 3 cubed and you take out the 3 and place it in front of the cube root of 3 and multiply that 3 in the front by 5 to get 15 times cube root of 3

Then, 2 times cube root of 3 + 15 times cube root of 3 equals 17 times the cube root of 3

You used the correct method of doing this problem

Answer 4

Yes.

Cube root of 24 = cube root of 8 (=2) times the cube root of 3
Cube root of 81 = cube root of 27 (=3) times the cube root of 3

So: (2 + 5*3) * cube root of 3 = 17 * cube root of 3

Answer 5

cuberoot of 24 = 2cuberoot3 (24 = 8 x 3)

cuberoot81= 3cuberoot3 (81 = 27 x 3)

So cuberoot24 + 5cuberoot81 = 2cuberoot3 + 5x3cuberoot3
= 17cuberoot3

Your solution is correct.

Answer 6

24^(1/3) + (5)81^(1/3)=
(2)3^(1/3) + (5)(3)3^(1/3)=
(2+15)3^(1/3)
= 17 (³√3)
Looks like you’re right…Or we’re both wrong.

Answer 7

24^(1/3) + 5(81^(1/3)) =

2(3^(1/3)) + 5(3(3^(1/3))) =

2(3^(1/3)) + 15(3^(1/3))) =

17(3^(1/3)).....

you're correct