I understand how to add fractions but what do I need to do know that there is a power involved? Someone help the examples I have are not helping me
2007-07-10 06:38:04 · 5 answers · asked by jmarc5069 1 in Science & Mathematics ➔ Mathematics
(7/3w)+(5/3w^2)
= (7w+5w^2)/3
= w(7 +5w)/3
I have assumed that 7/3w means 7w/3 and not 7/(3w).
If you meant 7/(3w) +5/(3w^2), then the answer is:
7w/(3w^2)+5/(3w^2) = (7w+5)/(3w^2).
2007-07-10 06:49:41 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
(7/3w)+(5/3*w^2)
multiply the first expression by (w / w)
...
= (w/w)*(7/3w) + (5/ 3*w^2)
= (7w/3*w^2) + (5/ 3*w^2)
= (7w + 5)/ 3*w^2
2007-07-10 06:44:03 · answer #2 · answered by mark r 4 · 0⤊ 0⤋
(7/3w)+(5/3w^2)
I am rewriting that as
7w/3 + 5w^2/3
= (7w + 5w^2) / 3
= w(7 + 5w) / 3
2007-07-10 06:44:41 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
You can't do anything with that except factor it.
w(7/3 + 5/3w)
2007-07-10 06:41:05 · answer #4 · answered by de4th 4 · 0⤊ 1⤋
get like denominators
(7W/3W^2)+(5/3W^2)
= (7W+5)/(3W^2)
2007-07-10 06:43:16 · answer #5 · answered by mking785 2 · 0⤊ 0⤋