please help me.?

0 ⤊

factor completely with respect to the integers.

x^4+12x^3+4x^2+48x

2007-07-10 05:50:25 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

x^4+12x^3+4x^2+48x
= (x^4+12x^3) + (4x^2+48x)
= x^3 (x + 12) + 4x (x + 12)
= (x + 12)(x^3 + 4x)
= (x + 12)(x)(x^2 + 4)

2007-07-10 05:55:16 · answer #1 · answered by Mathematica 7 · 0⤊ 1⤋

x^4+12x^3+4x^2+48x
= x^2(x^2+12x) +4(x^2+12x)
= (x^2+12x)(x^2+4)
=x(x+12)(x^2+4)

2007-07-10 13:00:22 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

x^3(x + 12) + 4x(x + 12) =

(x+12)(x^3 + 4x) =

x (x+12)(x^2 + 4)

2007-07-10 12:56:50 · answer #3 · answered by gfulton57 4 · 0⤊ 0⤋