Information is missing to answer this question accurately. People are making assumptions here. You stated that the dad is homozygous but you did not state whether he is homozygous recessive or dominant. I feel this information is crucial to also determining what the genotype of the mom may be. Yes, some may know if it is a recessive or dominant allele but its not stated therefore it leaves the question open to the possiblity of more than one answer.
For instance, if dad is homozygous dominant he would be BB and then mom would have to be bb this would end up with all the children being heterozygous (Bb) meaning all of them, 100% (4:0) would have a widows peak.
However, if dad is homozygous recessive he would be bb and then mom could be Bb or BB and this would end up with the children, if the mom is Bb with a 50% chance (2:1) of the children with a widows peak and if she is BB, then there is a 100% (4:0) chance they will end up with a widows peak.
Therefore there is more than one answer to this question since certain information is not precise.
Hope that helps. ;)
2007-07-10 05:46:13
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answer #1
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answered by Anonymous
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Homozygous means ww or WW And if the widows peak is a recessive trait than the mother has to be ww. If you do a test monohybrid cross with them. So you first cross WW (assuming that that would be the alleles.) with ww. The genotypic (means what it is.) ratio for that is WW: 0
Ww: 4
ww:0
And the phenotypic (means what is seen) ratio is. Widows Peak: 4
No widows peak:0
That would be what it would be when we are assuming that the gene is WW. Now all you have to do is plug ww into the equation to see what the ratios would be with those alleles. If a few of the children come out with widow peaks we can assume that the gene is WW.
I hope this wasn't too confusing for you. : )
2007-07-10 07:09:32
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answer #2
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answered by Kaitlyn 2
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Since the father is HOMOzygous (that means he has the same allele on both chromosomes) and since widow's peak is dominant, all the children will have widow's peak. Because the mother does not have a peak, she must be homozygous for the recessive gene (no peak), therefore all the children would be Ww (heterozygous).
2007-07-10 05:07:26
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answer #3
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answered by kt 7
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Okay, make a punnett square. Dad's is WW (homozygous) and Mom is ww (because she doesn't show a widow's peak and it is a dominant trait she has to be homozygous recessive or ww).
......W W
w Ww Ww
w Ww Ww
Genotype - 100% of children will be Ww
Based on the punnet square, all children will have a widow's peak (phenotype).
2007-07-14 02:54:29
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answer #4
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answered by aliasiddiqui 1
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Your homozygous father can only give widow's-peak-dominant genes. But the mother has no widow's peak (which is a dominant trait), which means she is homozygous recessive, and can only pass down her recessive genes. There is only one possibility.
All children will be Ww; heterozygous for widow's peak. They will all show the dominant widow's peak.
2007-07-10 05:04:17
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answer #5
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answered by Valerie G 2
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The allele for widows peak is a dominant allele i.e. W and that for normal is recessive i.e. w . So, father is WW and mother is ww. Hence, by punnett square, 100 % of their children will be heterozygous for widows peak and their genotyoe will be "Ww".
2007-07-10 06:00:45
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answer #6
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answered by Merajzai 2
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if the dad is homozygous then he is WW
the mom doesn't have, recessive, so ww.
punnett square
so the kids would all have widows peak and be heterozygous
2007-07-10 05:12:04
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answer #7
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answered by Anonymous
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ok so the dad is HH for the widows peak and the mom is hh meaning that when it cross there will be Hh:Hh:Hh:Hh or 100% chance that all the children will be heterozygous for the widows peak
2007-07-10 05:04:34
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answer #8
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answered by George K 1
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ok so a dinner sq. would tell the child would have 25% ruled characteristics 25% homozygous and 50% recessive. The recessive ability u would have a widows height. the percentages coach u how possibly it it to take place. i wish this facilitates.
2016-09-29 10:53:51
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answer #9
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answered by ? 4
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Use a Punnett square, its a 50-50 chance.
50% - will not have widows peck
50% - widows peck
phenotype: the things you can see, like hair color, skin color, that sort of thing.
genotype: is the letter it stands for. you can use any letter (sometimes they give you a letter and you can use that)
lets use A.
A a
___________
a I Aa l aa I
I ------ I------ I
a I Aa l aa I
__________
okay i tried to make a punnett square to show you. lol.
genotype: 50% - Aa 50% - aa, OR 1/2 - Aa 1/2 - aa
2007-07-10 05:17:18
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answer #10
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answered by What? 6
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