please answer this equation...thank you..!!!?

Question

given equation T=2pi square root of L/g
find the equation for: a. L and b. g

Answer 1

T = 2π √(L/g)
=> (T/2π) = √(L/g)
=> L/g = T^2 / (4π^2)
So L = T^2 g / (4π^2)
and g/L = 4π^2 / T^2
so g = 4π^2 L / T^2.

Answer 2

T=2pi square root of L/g
T^2=(2pi square root of L/g)^2
T^2=4pi^2 * L/g

(T^2)/(4pi^2 )= L/g
then:

a) (T^2)/(4pi^2 )*g= L

b) L/[(T^2)/(4pi^2 )]= g
g=4pi^2L/(T^2)

Answer 3

2pi sqrt(L/g)=T
or,4*pi^2L/g=T^2 [squaring both sides]
or 4*pi^2L=T^2*g
or L= T^2*g/4*pi^2
Again,
4*pi^2*L/g=T^2
1/g=T^2/4*pi^2*L
or g=4*pi^2 *L/T^2

Answer 4

T = 2π √(L/g)
(T)² =(2π √(L/g))²........sq both sides
T² = 4 π² L/g
g = 4 π² L/T²
&
L = (gT²)/(4 π² )