the integer m is between 40 and 100. when m is divided by 3, the remainder is 2. when m is divided by 7, the remainder is 1. what is the one possible value of m?
2007-07-09 21:13:14 · 6 answers · asked by [Music = love] <3 2 in Science & Mathematics ➔ Mathematics
Since m/7 has a remainder of 1,
we know m = 7k + 1, for some integer k
If k = 6, m = 43
if k = 7, m = 50
if k = 8, m = 57
etc... possible numbers are 43, 50, 57, 64, 71, 78, 85, 92, 99.
Since m/3 has a remainder of 2,
we know m = 3j + 2, for some integer j.
So (m - 2) must be divisible by 3.
If you subtract 2 from the candidate numbers above, you get:
41, 48, 55, 62, 69, 76, 83, 90, 97.
48, 69 and 90 are all divisible by 3, so 50, 71 and 92 are all possible values of m.
50/3 = 16 + remainder of 2
50/7 = 7 + remainder of 1
71/3 = 23 + remainder of 2
71/7 = 10 + remainder of 1
92/3 = 30 + remainder of 2
92/7 = 13 + remainder of 1
Apparently there are three possible values of m. Are you sure you stated the problem correctly?
2007-07-09 21:25:39 · answer #1 · answered by Bramblyspam 7 · 0⤊ 0⤋
50
2007-07-10 04:32:31 · answer #2 · answered by girly 2 · 0⤊ 0⤋
By hit and trial, the value of m = 50
2007-07-10 04:21:33 · answer #3 · answered by seminewton 3 · 0⤊ 0⤋
It could be 50 or 71 or 92. They are all possible answers. You didn't give enough information to know which one it is, though.
2007-07-10 04:19:15 · answer #4 · answered by Escuerdo 3 · 0⤊ 0⤋
50 is the number.
2007-07-10 04:16:12 · answer #5 · answered by Shobiz 3 · 0⤊ 0⤋
maybe 50
2007-07-10 04:33:23 · answer #6 · answered by ASHPUT WALEPUK 2 · 0⤊ 0⤋