x^3 - 1
I can't remember what to do when it's x^3 and there's no x to factor out.
Thanks
2007-07-09 18:20:36 · 7 answers · asked by Hmmm Andrew ♣ 2 in Science & Mathematics ➔ Mathematics
x^3 - 1
= (x - 1) (x^2 + x + 1)
The pattern is:
a^3 - b^3
= (a - b) (a^2 + ab + b^2)
2007-07-09 18:25:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(x- 1)(x^2 + x + 1)
2007-07-10 01:25:20 · answer #2 · answered by rydhel1016 3 · 0⤊ 0⤋
This factors into (x-1)(x^2 + x + 1).
2007-07-10 01:41:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
It's a special form (x-1)(x^2+x+1)
2007-07-10 01:24:34 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋
using the formula a^3 - b^3 = (a-b)(a^2+ab+b^2)
x^3-1 = (x-1)(x^2+x+1)
2007-07-10 01:26:53 · answer #5 · answered by Jain 4 · 0⤊ 0⤋
= (x - 1)(x^2 + x +1)
hope this helps
try out some other examples, and in no time, you'll become a pro at this...
2007-07-10 01:24:13 · answer #6 · answered by brother Mohammed 2 · 0⤊ 0⤋
(x-1)(x²+x+1)
It's a difference of two cubes.
a³-b³=(a-b)(a²+ab+b²)
2007-07-10 01:23:40 · answer #7 · answered by jsoos 3 · 0⤊ 0⤋