math help!?

Question

1. the legs of a right triangle are 5 and 2. find the meeasure of the hypotenuse of this triangle.

can u tell me wat formula to use?

2. a base angle in an isoceles triangle has a measure of 50 degrees. find the number of degrees in the vertez angle of this isoceles triangle?

how do u do this 2nd question?

Answer 1

1. pathagorean theorom...a^2 + b^2 = c^2
2. an isoceles triangle has two angles that are the same (on the base) so fine the one you don't know. There are 180 degrees in a triangle 50 + 50 = 100 the remaining angle is...
i think thats what number 2 is asking

Answer 2

1. Where A and B are legs of a right triangle, and C is the hypotenuse (longest side), the "Pythagorean Theorem" states that A^2 + B^2 = C^2

So in this case, plug in A= 5 and B=2
to get
5^2 + 2^2 = C^2
25 + 4 = C^2
C = square root of 29

2. In all triangles, the three angles add up to 180 degrees.
In an Isoceles triangle, the two base angles are congruent, or equal in measure.
So if the Base Angle = 50, the other is also 50.
180 - 100 leaves 80 degrees for the Vertex Angle (between the two equal Base Angles).

Answer 3

1. Imagine a triangle. The longest side is called the hypotenuse. The other 2 sides squared and added together = the hypotenuse squared:
a squared + b squared = c squared, where c is the hypotenuse.
2. Enough people have answered this question.