Try dividing by (x-2) using long division:
x^3 - 3x^2 + 0x +4
------------------------
x - 2
............x^2
...........--------------------------
x - 2.../ x^3 - 3x^2 + 0x + 4
.........- (x^3 - 2x^2)
...........----------------
.................... - x^2 + 0x
............x^2 - x
...........--------------------------
x - 2.../ x^3 - 3x^2 + 0x + 4
.........- (x^3 - 2x^2)
...........----------------
.................... - x^2 + 0x
....................- (-x^2 +2x)
......................------------------
.......................( - 2x + 4 )
.....................x^2 - x - 2
...........--------------------------
x - 2.../ x^3 - 3x^2 + 0x + 4
.........- (x^3 - 2x^2)
...........----------------
.................... - x^2 + 0x
....................- (-x^2 +2x)
...................------------------
......................( - 2x + 4)
..................... - (-2x + 4)
......................------------
............................0
(x - 2)(x^2 - x - 2)
(x-2)(x+1)(x-2)
check your work by multiplying these factors
to see if the result is x^3 - 3x^2 + 4
Check: (x-2)^2 * (x+1)
= (x^2 -4x + 4)(x +1)
(x^3 - 4x^2 + 4x) + (x^2 -4x + 4)
x^3 -3x^2 +4 this seems to work
Note 1:
The trick to testing what to divide by:
(A) Most commonly used factors in math problems are
(X + 1) or (X - 1), (X + 2) or (X - 2)
So I would try one of these first to see if it divides evenly
(B) Since the constant/last term in the equation is "4"
Then the possible factors to try are factors of 4
(+1, -1, +2, -2, +4, -4)
So after (X + 1) and (X - 1) did not work
then I tried dividing by (X + 2) or (X - 2)
Note 2:
After you find that (X - 2) divides evenly,
Check again to see if the remainder can factor.
In this case, remainder (x^2 - x - 2) factored again into
(x+1)(x-2)
The final answer
(x-2)(x+1)(x-2)
can also be written as
(x + 1)(x - 2)^2
Note 3:
Always check your work.
It is easier to multiply the factors to get the original answer,
than it is to divide.
The hardest thing is watching the minus signs when
you multiply and subtract during steps of long division.
So checking your work will make sure
you do not have multiplication or sign errors.
2007-07-09 16:05:35
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answer #1
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answered by Nghiem E 4
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you can't factor anything out so u have to the quadratic formula.
http://en.wikipedia.org/wiki/Quadratic_formula#Quadratic_formula
2007-07-09 22:37:38
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answer #2
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answered by KIKI 1
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