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-5x^2 -x(x(4/x)+10) = -4x

-5(x-3) + 2 (3 - x) + x = -14 + x

2007-07-09 15:12:48 · 2 answers · asked by Arthur M 1 in Science & Mathematics Mathematics

2 answers

-5x^2 -x(x(4/x)+10) = -4x
-5x^2 - 4x -10x = -4x
5x^2 + 10x = 0
x^2 + 2x = 0
x(x + 2) = 0

x = 0 or x = -2 are solutions, however, since we have x in the denominator in the original equation, that rules out the x=0 solution (can't have 0 in a denominator). The only remaining solution is x=-2.

-5(x-3) + 2 (3 - x) + x = -14 + x
-5x + 15 + 6 - 2x + x = -14 + x
-6x + 21 = -14 + x
35 = 7x
x = 5

2007-07-09 15:17:29 · answer #1 · answered by McFate 7 · 0 0

firstly simplify the first equation

1) -5x^2 - x[4+10] = -4x

which gives

-5x^2 - 14x = -4x

multiply both sides by -1

5x^2 + 14x = 4x

then substract 4x from both sides

5x^2 + 10x = 0

5x ( x+2) = 0

x = 0, -2


simiplify the second equation

-5x +15 +6 - 2x + x = -14 + x

21 - 6x = -14 + x

21 + 14 = x + 6x

35 = 7x

x = 35/7 = 5

2007-07-09 22:24:31 · answer #2 · answered by Aslan 6 · 0 0

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