how can you factor 3a^2?

0 ⤊

is it possible??

2007-07-09 12:35:52 · 4 answers · asked by _cupcakes_ 1 in Science & Mathematics ➔ Mathematics

also, can someone help me solve the rational expression 5-y/(3y)^2 * 9y^2/y-5

2007-07-09 12:39:53 · update #1

3a^2 = (3)(a)(a)

y/(3y)^2 * 9y^2/y-5 = y/(y-5)

2007-07-09 12:45:19 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

5-y/(3y)^2 * 9y^2/y-5

5-y/9y^2 * 9y^2/y-5

= 5-y/y-5 = 5-y/-(5-y) = -1

And 3a^2 is fully factored

2007-07-09 19:45:08 · answer #2 · answered by SS4 7 · 0⤊ 1⤋

3a^2 is already factorized, canot be done further.

2007-07-09 19:38:55 · answer #3 · answered by Anonymous · 0⤊ 1⤋

i believe all you can do is ... a(3a) that's how far you can go.

2007-07-09 19:41:26 · answer #4 · answered by EGD173 2 · 0⤊ 1⤋