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simplify each radical expression:
1.
-√m^4n^7

and

2.
1/5√[(75xy^2) (z^3)]

2007-07-09 11:39:01 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Assuming you mean this:
=-sqrt(m^[4(n^7)]
=-sqrt(m^2(n^7) * m^2(n^7))
=-m^2(n^7)

(1/5) sqrt[(75xy^2) (z^3)]
=(1/5) sqrt(75) sqrt(x) sqrt(y^2) sqrt(z^3)
=(1/5) sqrt(25*3) sqrt(x) sqrt(y^2) sqrt(z^2 * z)
=(1/5) sqrt(25) sqrt(3) sqrt(x) sqrt(y^2) sqrt(z^2) sqrt(z)
=(1/5)*5*y*z* sqrt(3) sqrt(x) sqrt(z)
=yz sqrt(3xz)

2007-07-09 11:59:42 · answer #1 · answered by whitesox09 7 · 0 0

Hello,

rewrite - sqrt(m^4 n^6 n) taking out the prefect squares we have
-m^2n^3sqrt(n)

rewrite as 1/5 sqrt(25*3*xy^2z^2z)

taking out the prefect squares we have

(1/5)*5yz sqrt(3xz) or yz* sqrt(3xz)

Hope This Helps!

2007-07-09 19:02:05 · answer #2 · answered by CipherMan 5 · 1 0

1. = -m^2n^3 sqrt n

2 = 1/5 sqrt(75x y^2 z^3)
= 1/5 * 5yz sqrt 3 x z
= yz sqrt(3xz)

2007-07-09 19:08:14 · answer #3 · answered by Matt D 6 · 0 0

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