what is the period for cos(4x)?

Question

can someone help me out on this what i need to know is what is the period of the sine curve cos(4x) for x = 0 to 2 pi

i need to know the period in degrees and radians please.

any help gladly appreciated.

Thanks
Eggie

Answer 1

Hello,

The 4 indicates that there are 4 cycles in a normal period and the normal period is 2pi or 360 so we divide by 4 and have pi/2 or 90 degrees.

Hope This Helps!!

Answer 2

Cos(4x) is a sine waveform shifted by 90 degrees.

If it was cos(x) the waveform will complete 1 cycle in 2*Pi radians and cos (4x) will complete 4 cycles in 2*Pi radiance because it's frequency is 4 times the fundamental frequency
1 cycle of the fourth harmonic will be completed
in 2*Pi/4 = 1.570796 radians This is an angle in radians and not a period. Periodic time = T= time to complete 1 cycle.
If T=1/f where f is the frequency of the fundamental, then the period of the fourth harmonic is 1/(4f) seconds
Note that the value of x at any given instant is given by
x = 2*Pi*f*t

Answer 3

the period is pi/2 or 90 degrees

That means there would be 4 periods between 0 and 2 pi

Answer 4

cos 4x repeats every 360 / 4° = 90°
Period = 90° or π / 2

Answer 5

Hello my friend!

Every cosinus function has the only frequence of 2 pi so 360 degree!
Consider a point on a trigonometrical circle, it is only when you made a complete tour that the same cosinus values of any angles remain the same!

I Hope i helped!

Answer 6

period is found by 2pi/B or 2pi/4 which is pi/2 or 90 degrees

Answer 7

y=cos(4*x)

0 to 6.28 rads
0 to 360 deg
0 to 400 grads

Answer 8

4x = pi
x = pi / 4 . . . answer