factor completely with respect to the integers.
1-64x^3
thanks!
2007-07-09 08:37:34 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the expression is the differcence of perfect cubes
a^3 - b^3 = (a - b) (a^2 + ab + b^2)
1 - 64x^3
1^3 - 4^3 x^3
1^3 - (4x)^3
(1 - 4x) (1 + 4x + 16x^2)
2007-07-09 08:45:18 · answer #1 · answered by 7 · 0⤊ 1⤋
howdy there! here is the respond. f(0)=4 f(a million)=2 f(n)=f(n-a million)-f(n-2) --> f(2)=f(2-a million)-f(2-2) --> f(2)=f(a million)-f(0) --> f(2)=2-4 --> f(2)=-2 f(3)=f(2)-f(a million) --> f(3)=-2-2 --> f(3)=-4 --> f(4)=f(3)-f(2) --> f(4)=-4-(-2) --> f(4)=-4+2 --> f(4)=-2 The values of the 1st 5 values of the recursive function are 4, 2, -2, -4 and -2. wish it enables!
2016-12-14 03:49:58 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(1+4x)(1 -4x +16x^2)
2007-07-09 08:47:52 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋