Thats just the tip of the iceberg!!?

Question

"Thats just the tip of the iceberg" is a popular expression. It means that what you see is only part of the overall problem. if most of an iceberg is out of sight below the water level what is the most likely dinsity of the ice berg? (assume a density of 1.03 g/mL for seawater)

a) 0.88 g/cc
b) 1.23 g/cc
c) 0.23 g/cc
d) 4.14 g/cc

[Pick the correct answer!!]-Answer Correctly!!

Answer 1

a) 0.88 g/cc
If the density were larger, the iceberg would sink to the bottom. But, since it floats, on could assume that the density is less than that of the salt water. Because most of the berg is submerged, the densities are relatively close in value. The only answer that is close to the density of the water but still below is a, 0.88 g/cc.

Answer 2

There are but two possibilities: a and c, the berg would sink for the other two answers.

The berg will float when its weight equals the weight of the displaced ocean water. Thus, W = w; where W is the berg weight and w is the water weight. So we have W = V Rho g = v rho g = w Then the ratio V/v = rho/Rho; so that V = v (rho/Rho); where Rho is the mass density of the berg and rho is the mass density of the water. V is the volume of the berg and v is the volume of displaced water.

As some of V is visible above the volume of water (the tip of the iceberg), we know that V > v; therefore, it follows that rho > Rho, which means the mass density of water has to be greater than the mass density of the ice. And that leaves us with a and c as feasible answers.

As V = AH = v (rho/Rho) = Ah (rho/Rho); where A is the footprint area of the displaced water and iceberg, H is the height of the berg, and h is the height of the displaced ocean volume, we have H/h = rho/Rho. Thus, the height of the berg H = h (rho/Rho)

If Rho = .88 g/cc, then H/h = rho/Rho = 1.03/.88 and the height of the berg would be just a bit higher than the displaced water. So the tip would be relatively small. But if Rho = .23 g/cc, then H/h = 1.03/.23 and the tip would be quite large because the berg would be about four times higher than the displaced water volume. So, given what we know about the tip of the iceberg, a) has to be the correct answer.

Answer 3

A iceberg is merely a large ice cube. Its merely a question of buoyancy due to the difference of density. From 50º C to 4º C water gets heavier (i.e. the density rises) from 0.988 g/cc to 1.000

When water gets colder than 4º C it becomes lighter, at 0º C it becomes ice and it weighs 0.9998425 grams per cm3, lets say 1 g/cc.

The water temperature in the polar areas is 4º C at maximum, so icebergs will float.

Another aspect is the salinity of the seawater. Salinity makes water heavier. Salty ocean water weighs 1.025 g/cc, making the iceberg even easier to float.

The icebergs are slightly lighter than the cold seawater, therefore the ice provides enough buoyancy to float. The answer is most likely A, and could not be any of the others.

Answer 4

B

If sea water has a density of 1.03 g/ml, and an iceberg is mostly, but not entirely below the water level, than the iceberg must have a density that is close to that of seawater, but slightly larger so that it would partially sink.

Answer 5

The ice being more expanded than the water will be a little less than the water density, therefore I'd say...
Ans..a)..0.88g/cc

Answer 6

for those who said b...YOU'RE WRONG.

if it was more dense, then it would completely sink.
the answer is obviously A

Answer 7

b)