2007-07-09 05:44:32 · 25 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Between 1:05 pm and 1:06 pm (provided there is no second hand.)
If the hands are advanced by gears on the minute, than at exactly 1:05:05 pm (including the second hand.)
AND
Provided the clock has a 12 hour face and not a 24 hour face! (If you are including the second hand and continuous sweep of all hands, it's a different story.)
.
2007-07-09 06:07:39 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Hour hand moves 30 deg each hour and .5 deg each minute.
Minute hand moves 6 degrees each minute.
At 1:05, hour hand is slightly past the 30 deg (1 on the dial):
30 + .5m = 6m, or 30 = 5.5m, so m = 5.4545...
So the time of their exact same position is 1:05 and .4545 of a minute or 1:05 and 27.2727... seconds
2007-07-09 06:08:56 · answer #2 · answered by John V 6 · 1⤊ 0⤋
12 o' clock in the morning.
2007-07-09 07:38:03 · answer #3 · answered by Angel 2 · 0⤊ 0⤋
if you're talking about all 3 hands it has to be 12:00 am midnight
if only the two then 1:05pm
2007-07-09 06:38:49 · answer #4 · answered by Marty B 2 · 0⤊ 0⤋
5 minutes after 1
2007-07-09 05:46:58 · answer #5 · answered by the_twenty_car 3 · 3⤊ 1⤋
1:06
2007-07-09 05:52:06 · answer #6 · answered by Mrs. Kennedy 2 · 0⤊ 0⤋
Given homogeneous continuous weep, very slightly after 1/60 second after 12:01:01.
2007-07-09 05:49:59 · answer #7 · answered by Uncle Al 5 · 1⤊ 0⤋
right after 1:05
2007-07-09 05:49:32 · answer #8 · answered by miggitymaggz 5 · 0⤊ 0⤋
13:05 and 30 seconds.
2007-07-09 05:47:04 · answer #9 · answered by Anonymous · 3⤊ 0⤋
1:05
2007-07-09 05:48:05 · answer #10 · answered by neonatheart 4 · 0⤊ 0⤋