Solve the equation below.
(a + 2)(a + 13)=0
A. a = 2 or a = 13
B. a = -2 or a = -13
C. a = -2 or a = 2
2007-07-09 05:30:53 · 8 answers · asked by Chillin with my peeps 1 in Science & Mathematics ➔ Mathematics
a + 2 = 0
Tramspose 2
a + 2 - 2 = 0 - 2
a = - 2
- - - - - - -
a + 13
Transpose 13
a + 13 - 13 = 0 - 13
a = - 13
- - - - - - -
The answer is B
a = - 2 or a = - 13
- - - - - - - -s-
2007-07-09 07:41:42 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Hey there!
Recall the zero-product property.
Let p and q be the factors of the polynomial. If pq=0, then p=0 or q=0.
Here's the answer using the zero-product property.
(a+2)(a+13)=0 -->
a+2=0 or a+13=0 -->
a=-2 or a=-13
So the answer is a=-2 or a=-13.
Hope it helps!
2007-07-09 12:36:39 · answer #2 · answered by ? 6 · 0⤊ 0⤋
The product equals 0 when either factor equals 0.
a+2=0 when a=-2
a+13=0 when a=-13
B is the answer.
2007-07-09 12:35:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
set each equal to zero
a+2=0 a+13=0
a=-2 a=-13
2007-07-09 12:33:27 · answer #4 · answered by leo 6 · 0⤊ 0⤋
set each equation in the parentheses to 0, then solve algebraicly
like this:
a+2=0
a=-2
a+13=0
a=-13
2007-07-09 12:52:19 · answer #5 · answered by Ren B 1 · 0⤊ 0⤋
Set each part equal to zero:
a+2 = 0
a = -2
a + 13 = 0
a = -13
so the anser is B
2007-07-09 12:35:08 · answer #6 · answered by jules0512 2 · 0⤊ 0⤋
answer is b
solve that by equating each factor to zero:
(a+2) = 0 therefore a = -2 (by transposition)
(a+13) = 0 therefore a = -13 (again, by transposition)
2007-07-09 12:38:19 · answer #7 · answered by armanomi 2 · 0⤊ 0⤋
Do your OWN homework or I'm gonna tell!
2007-07-09 12:39:10 · answer #8 · answered by Anonymous · 0⤊ 0⤋