In acid base titration 25.62 mL of an NaOH solution are needed to neutralize 26.23mL of a 0.1036 HCl solution?

Question

Whats the value of M subscript h+ in the HCl solution? and
M subscript OH( negative charge) in the NaOH solution? and
M subscript NaOH from M subscripts OH with a negative charge.?

Answer 1

HCl is a strong acid
NaOH is a strong base
HCl + NaOH >> NaCl + H2o
Moles HCl = 26.23 x 0.1036 /1000 = 0.00272 = moles NaOH
25.62 mL = 0.0256
M = moles / L = 0.00272 / 0.0256 = 0.106 M

Answer 2

1. 26.23 x 0.1036/1000
2. same
3. multiply answer 1 by 1000/25.62