a train moving with a constant velocity of 0.5m/s is about to pass in an intersection whose distance is 8.0m.?

Question

..cont..
At the same instant, a car with a speed of 1.5m/s & 10m away from the intersection (perpendicular to the railway), is in a hurry to beat the warning signal. If the car kept a constant acceleration of 0.25m/s^2, is it possible for the car to pass through the intersection without colliding w/ the train?..

2.) The motion of the truck is given by the equation: v=dt+ct^2, where d=50cm/s^2 & c= -5cm/s^3. Determine the..
(a) average acceleration from t=1.5s to t=5.0s
(b) instantaneous acceleration when t=3.0s

3.) the motion of a particle is described by the equation:
x=ct^2+b, where c=10cm/s^2, & b=5cm. Determine the instantaneous velocity when t=1.75s.

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Answer 1

.....and you want us to do your homework? look. we had to learn this and paid our dues. now it is your turn. get off of the computer and finish your homework.

Answer 2

a train moving with a constant velocity of 0.5m/s is about to pass in an intersection whose distance is 8.0m.?
..cont..
At the same instant, a car with a speed of 1.5m/s & 10m away from the intersection (perpendicular to the railway), is in a hurry to beat the warning signal. If the car kept a constant acceleration of 0.25m/s^2, is it possible for the car to pass through the intersection without colliding w/ the train?..

Ans: The train will need 16 seconds to reach the intersection ( 8 / 0.5 = 16 )

The car is travelling at a speed of 1.5 m/s and is at a distance of 10m. Even without accelerating, the car will pass the intersection in 6.667 seconds and so yes, the car will pass the intersection without colliding with the train. No need for other calculations.

Q.3 3.) the motion of a particle is described by the equation:
x=ct^2+b, where c=10cm/s^2, & b=5cm. Determine the instantaneous velocity when t=1.75s.

What is x. ct^2 will have the units of cm and b also has units of cm. What is the relation for velocity?

Answer 3

A practice has an engine that propels it forward, we could say at a fee of 60 mph, so being on the practice you're additionally shifting at 60 mph. the instant your ft go away the floor your momentum for sure starts at 60 mph, in spite of the incontrovertible fact that until you have an engine up your *** or in a no ecosystem ecosystem, you're problem to air rigidity/friction, so which you will decelerate. once you bounce in the air you're up in the air for under a 2d, so the quantity of velocity lost is particularly measurable, so once you come down that's fractionally off from the place you jumped. we could say you are able to bounce 50 ft in the air right now up you may lose measurable floor. even nonetheless it truly is particularly uncomplicated and entire undemanding sense they some how convince human beings otherwise because of the fact it disproves the earth rotating on the nonsensical fee we are instructed it rotates at.